展开 (13(81-36y+4y^2))/9

解答

展开

\frac{13 ( 81 - 36 y + 4 y ^{2} )}{9}

\frac{52 y ^{2}}{9} - 52 y + 117

求解步骤

\frac{13 ( 81 - 36 y + 4 y ^{2} )}{9}

乘开

13 (81 - 36 y + 4 y^{2}) : 1053 - 468 y + 52 y^{2}

= \frac{1053 - 468 y + 52 y ^{2}}{9}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1053 - 468 y + 52 y ^{2}}{9} = \frac{1053}{9} - \frac{468 y}{9} + \frac{52 y ^{2}}{9}

= \frac{1053}{9} - \frac{468 y}{9} + \frac{52 y ^{2}}{9}

数字相除:

\frac{1053}{9} = 117

= 117 - \frac{468 y}{9} + \frac{52 y ^{2}}{9}

数字相除:

\frac{468}{9} = 52

= 117 - 52 y + \frac{52 y ^{2}}{9}

改写为标准形式

= \frac{52 y ^{2}}{9} - 52 y + 117

e x p an d \frac{( ( n ) ( 2 n - 1 ) ( 2 n + 1 ) )}{3}

e x p an d \frac{3 y ^{4} ( 2 u ^{5} - 1 )}{u}

e x p an d - (x ln (x) - x) (y x)

e x p an d \frac{2 ( 3 17 - 1 )}{19}

e x p an d \frac{4 ( x - 4 )}{x ( x + 3 )}