展开 C(2,-5)4

解答

展开

C (2, - 5) 4

4 \cdot 2 C, - 4 \cdot 5 C

求解步骤

C (2, - 5) \cdot 4

= 4 (2, - 5) C

使用分配律:

a (b - c) = ab - a c

a = C \cdot 4, b = 2,, c = 5

= C \cdot 4 \cdot 2, - C \cdot 4 \cdot 5

= 4 \cdot 2 C, - 4 \cdot 5 C

e x p an d \frac{1}{( s + 20 ) ^{2}}

e x p an d 22 \frac{9 c}{5} + 32

e x p an d \frac{( n + 1 ) ^{3} !}{( n ! ) ^{3}}

e x p an d (e + d)^{2} - 18 (e + d) + 65

e x p an d 9 x - (2 x - 15 = 42)