展开 (2x+z=7,)*(x-y+2z=6)

解答

展开

(2 x + z = 7,) \cdot (x - y + 2 z = 6)

2 x^{2} - 2 x y + 4 x z = 6

求解步骤

(2 x + z = 7,) (x - y + 2 z = 6)

= (2 x + 7 =, z) (x - y + 2 \cdot 6 = z)

打开括号

2 xx + 2 x (- y) + 2 x \cdot 2 z = 6 + z = 7, x + z = 7, (- y) + z = 7, 2 z = 6

使用加减运算法则

+ (- a) = - a

2 xx - 2 x y + 2 \cdot 2 x z = 6 + z = 7, x - z = 7, y + z = 7, 2 z = 6

乘开

2 xx - 2 x y + 2 \cdot 2 x z : 2 x^{2} - 2 x y + 4 x z

2 x^{2} - 2 x y + 4 x z = 6

e x p an d S (t)

e x p an d \frac{1}{( a + 3 ) ^{2}}

e x p an d \frac{d x}{x ( x + 10 ) ( x - 3 )}

e x p an d 2 - 5

e x p an d \frac{1}{( x ^{2} + 1 ) ( s + 2 ) ( s + 3 )}