erweitern (ln(0.5x+0.5)+2.4)^2

Lösung

erweitern

(ln (0.5 x + 0.5) + 2.4)^{2}

ln^{2} (0.5 x + 0.5) + 4.8 ln (0.5 x + 0.5) + 5.76

Schritte zur Lösung

(ln (0.5 x + 0.5) + 2.4)^{2}

Wende Formel für perfekte quadratische Gleichungen an:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = ln (0.5 x + 0.5), b = 2.4

= ln^{2} (0.5 x + 0.5) + 2 ln (0.5 x + 0.5) \cdot 2.4 + 2. 4^{2}

Vereinfache

ln^{2} (0.5 x + 0.5) + 2 ln (0.5 x + 0.5) \cdot 2.4 + 2. 4^{2} : ln^{2} (0.5 x + 0.5) + 4.8 ln (0.5 x + 0.5) + 5.76

= ln^{2} (0.5 x + 0.5) + 4.8 ln (0.5 x + 0.5) + 5.76

e x p an d (- 10, 2) y (- 5, - 1)

e x p an d x (7 x - 248 = 5, y - 17) (2 y + 50 = x + 44)

e x p an d (4, 2, - 6) x (- 5, 3, - 2)

e x p an d \frac{x}{( s ^{2} + 4 ) ( s - 2 )}

e x p an d \frac{( x - 2 ) ( x - 4 )}{15}