展开 pi(4-2x)^2dx

解答

展开

π (4 - 2 x)^{2} d x

16 π d x - 16 π x d x + 4 π x^{2} d x

求解步骤

π (4 - 2 x)^{2} d x

(4 - 2 x)^{2} = 16 - 16 x + 4 x^{2}

= π (4 x^{2} - 16 x + 16) d x

打开括号

= π d x \cdot 16 + π d x (- 16 x) + π d x \cdot 4 x^{2}

使用加减运算法则

+ (- a) = - a

= 16 π d x - 16 π x d x + 4 π x^{2} d x

e x p an d (y - \frac{1}{x}) d x

e x p an d (y + 1) (y - 1)^{'}

e x p an d (a e - b g) (c f - d h)

e x p an d 2 (v \cdot r) + 2 (r - v)

e x p an d 3 (4 x + e^{x} + 6)