erweitern (pi(a^2+b^2)-4ab)/8

Lösung

erweitern

\frac{π ( a ^{2} + b ^{2} ) - 4 ab}{8}

\frac{π a ^{2}}{8} + \frac{π b ^{2}}{8} - \frac{ab}{2}

Schritte zur Lösung

\frac{π ( a ^{2} + b ^{2} ) - 4 ab}{8}

Multipliziere aus

π (a^{2} + b^{2}) - 4 ab : π a^{2} + π b^{2} - 4 ab

= \frac{π a ^{2} + π b ^{2} - 4 ab}{8}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{π a ^{2} + π b ^{2} - 4 ab}{8} = \frac{π a ^{2}}{8} + \frac{π b ^{2}}{8} - \frac{4 ab}{8}

= \frac{π a ^{2}}{8} + \frac{π b ^{2}}{8} - \frac{4 ab}{8}

Streiche

\frac{4 ab}{8} : \frac{ab}{2}

= \frac{π a ^{2}}{8} + \frac{π b ^{2}}{8} - \frac{ab}{2}

e x p an d \frac{( 2 ^{t} - 3 t ) t}{4 ^{t}}

e x p an d \frac{x ^{2} ( x - 5 )}{5}

e x p an d sin (2) (2 πn + \frac{π}{4})

e x p an d \frac{( s + 6 )}{s ( s + 1 ) ( s + 2 )}

e x p an d 3 (d H (x) = - \frac{1}{3} d x)