展开 (a'2+5a+4)^2

解答

展开

(a^{'} 2 + 5 a + 4)^{2}

4 (a')^{2} + 20 aa' + 16 a' + 25 a^{2} + 40 a + 16

求解步骤

(a^{'} 2 + 5 a + 4)^{2}

= (2 a^{^{'}} + 5 a + 4)^{2}

(a^{'} 2 + 5 a + 4)^{2} = (a^{'} 2 + 5 a + 4) (a^{'} 2 + 5 a + 4)

= (5 a + 2 a^{^{'}} + 4) (5 a + 2 a^{^{'}} + 4)

乘开

(a^{'} 2 + 5 a + 4) (a^{'} 2 + 5 a + 4) : 4 (a^{'})^{2} + 20 a a^{'} + 16 a^{'} + 25 a^{2} + 40 a + 16

= 4 (a^{'})^{2} + 20 a a^{'} + 16 a^{'} + 25 a^{2} + 40 a + 16

e x p an d \frac{5 ( 1 + 1153 )}{6}

e x p an d (0.0000005) (e^{1.19 E 39} - 1)

e x p an d (x^{2} + 5 x + 6) cos (3 x) d x

e x p an d - \frac{4 ( 4 2 - 2 )}{3}

e x p an d 14.11 \times 21