展开 (u+1/x)dx

解答

展开

(u + \frac{1}{x}) d x

u d x + \frac{d x}{x}

求解步骤

(u + \frac{1}{x}) d x

使用分配律:

a (b + c) = ab + a c

a = d x, b = u, c = \frac{1}{x}

= d xu + d x \frac{1}{x}

= u d x + \frac{1}{x} d x

\frac{1}{x} d x = \frac{d x}{x}

= u d x + \frac{d x}{x}

e x p an d (x - 2)^{2}

e x p an d x + 9^{2}

e x p an d \frac{x}{( s + 1 ) ^{2}}

e x p an d \frac{3 ( 3 - x )}{- x ^{2} - x + 9}

e x p an d \frac{3 x ^{2} + y}{x ( 1 - x y )}