vereinfachen (e^{-2it}+1)*te^{it}

Lösung

vereinfachen

(e^{- 2 i t} + 1) \cdot t e^{i t}

t (cos (2 t) - i sin (2 t) + 1) (cos (t) + i sin (t))

Schritte zur Lösung

(e^{- 2 i t} + 1) t e^{i t}

e^{- 2 i t} = cos (2 t) - i sin (2 t)

= e^{i t} t (cos (2 t) - i sin (2 t) + 1)

e^{i t} = cos (t) + i sin (t)

= t (cos (2 t) - i sin (2 t) + 1) (cos (t) + i sin (t))

e x p an d \frac{4}{( y + 1 ) ( y + 5 )}

e x p an d \frac{3 ( 3 x + 4 )}{( x - 4 ) ( x + 4 )}

e x p an d (\frac{- 36}{9} bi g)^{2} (9 - 36) 2

e x p an d \frac{( x + y )}{( x - y ) ( x - 2 y )}

e x p an d \frac{( 1 - 2 x )}{( 5 - x ) ( 3 - x )}