What is expand (-1.3)(2x+y-1=0) ?

The solution to expand (-1.3)(2x+y-1=0) is -2.6x-1.3y+1.3=0

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expand (-1.3)(2x+y-1=0)

expand

(- 1.3) (2 x + y - 1 = 0)

- 2.6 x - 1.3 y + 1.3 = 0

Solution steps

(- 1.3) (2 x + y - 1 = 0)

= (- 1.3) (2 x + y - 1 \cdot 0 =)

Distribute parentheses

= (- 1.3) \cdot 2 x + (- 1.3) y + (- 1.3) (- 1 = 0)

Apply minus-plus rules

+ (- a) = - a

2 (- 1.3) x + (- 1.3) y - 1 \cdot (- 1.3) = 0

Expand

2 (- 1.3) x + (- 1.3) y - 1 \cdot (- 1.3) : - 2.6 x - 1.3 y + 1.3

- 2.6 x - 1.3 y + 1.3 = 0

\frac{4 ( 1 - 3 x )}{( 3 x + 1 ) ^{3}}

(4 t - 8) d t

\frac{y ^{3}}{( 1 - x ) ^{2} + y ^{2}}

\frac{e ^{- x}}{( x ( x + 3 ) ( x - 1 ) )}

\frac{4 ^{k} k ^{2}}{( k + 1 ) ( k + 2 )}

What is expand (-1.3)(2x+y-1=0) ?
The solution to expand (-1.3)(2x+y-1=0) is -2.6x-1.3y+1.3=0