展開する (7x+2e^{7x+2})(3x^2)

解

展開する

(7 x + 2 e^{7 x + 2}) (3 x^{2})

21 x^{3} + 6 e^{7 x + 2} x^{2}

解答ステップ

(7 x + 2 e^{7 x + 2}) (3 x^{2})

分配法則を適用する:

a (b + c) = ab + a c

a = (3 x^{2}), b = 7 x, c = 2 e^{7 x + 2}

= (3 x^{2}) \cdot 7 x + (3 x^{2}) \cdot 2 e^{7 x + 2}

= 7 x (3 x^{2}) + 2 e^{7 x + 2} (3 x^{2})

簡素化

7 x (3 x^{2}) + 2 e^{7 x + 2} (3 x^{2}) : 21 x^{3} + 6 e^{7 x + 2} x^{2}

= 21 x^{3} + 6 e^{7 x + 2} x^{2}