erweitern ((3x+2)(2x+3))/(6x)

Lösung

erweitern

\frac{( 3 x + 2 ) ( 2 x + 3 )}{6 x}

x + \frac{13}{6} + \frac{1}{x}

Schritte zur Lösung

\frac{( 3 x + 2 ) ( 2 x + 3 )}{6 x}

Multipliziere aus

(3 x + 2) (2 x + 3) : 6 x^{2} + 13 x + 6

= \frac{6 x ^{2} + 13 x + 6}{6 x}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 x ^{2} + 13 x + 6}{6 x} = \frac{6 x ^{2}}{6 x} + \frac{13 x}{6 x} + \frac{6}{6 x}

= \frac{6 x ^{2}}{6 x} + \frac{13 x}{6 x} + \frac{6}{6 x}

Streiche

\frac{6 x ^{2}}{6 x} : x

= x + \frac{13 x}{6 x} + \frac{6}{6 x}

Streiche

\frac{13 x}{6 x} : \frac{13}{6}

= x + \frac{13}{6} + \frac{6}{6 x}

Teile die Zahlen:

\frac{6}{6} = 1

= x + \frac{13}{6} + \frac{1}{x}

e x p an d \frac{6 x + 58}{( x + 3 ) ( x + 8 )}

e x p an d \frac{9 x ( 4 x - 2 y ) ^{2}}{y ^{3}}

e x p an d (a + b e - l) (c + d e - l) - (f + g e) (h + j e)

e x p an d \frac{( s - 2 ) ^{2}}{( 1 - β ) ( 1 + β )}

e x p an d \frac{( x - 2 ) ( x + 1 )}{x ^{2} + 5}