展开 (1-cos(3t-3))/((t-1)^2)

解答

展开

\frac{1 - cos ( 3 t - 3 )}{( t - 1 ) ^{2}}

\frac{1 - cos ( 3 t - 3 )}{t ^{2} - 2 t + 1}

求解步骤

\frac{1 - cos ( 3 t - 3 )}{( t - 1 ) ^{2}}

(t - 1)^{2} = t^{2} - 2 t + 1

= \frac{1 - cos ( 3 t - 3 )}{t ^{2} - 2 t + 1}

e x p an d \frac{12}{( x + 3 ) ^{2}}

e x p an d co nj ug a d os (5 h + 3) (4 h - 5)

e x p an d (y = 4,) (z = - 2)

e x p an d (a^{^{'}} + b) c + ab c

e x p an d \frac{z - 5}{( z ^{2} - 10 z + 24 ) ^{2}}