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受欢迎的代数 >

l(x)=-x^2+12x-20

解答

l (x) = - x^{2} + 12 x - 20

解答

x = - \frac{- 12 + l + l ^{2} - 24 l + 64}{2}, x = - \frac{- 12 + l - l ^{2} - 24 l + 64}{2}

求解步骤

l (x) = - x^{2} + 12 x - 20

整理后得

l x = - x^{2} + 12 x - 20

交换两边

- x^{2} + 12 x - 20 = l x

将

l x

para o lado esquerdo

- x^{2} + 12 x - 20 - l x = 0

改写成标准形式

a x^{2} + b x + c = 0

- x^{2} + (12 - l) x - 20 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( 12 - l ) \pm ( 12 - l ) ^{2} - 4 ( - 1 ) ( - 20 )}{2 ( - 1 )}

化简

(12 - l)^{2} - 4 (- 1) (- 20) : l^{2} - 24 l + 64

x_{1, 2} = \frac{- ( 12 - l ) \pm l ^{2} - 24 l + 64}{2 ( - 1 )}

将解分隔开

x_{1} = \frac{- ( 12 - l ) + l ^{2} - 24 l + 64}{2 ( - 1 )}, x_{2} = \frac{- ( 12 - l ) - l ^{2} - 24 l + 64}{2 ( - 1 )}

x = \frac{- ( 12 - l ) + l ^{2} - 24 l + 64}{2 ( - 1 )} : - \frac{- 12 + l + l ^{2} - 24 l + 64}{2}

x = \frac{- ( 12 - l ) - l ^{2} - 24 l + 64}{2 ( - 1 )} : - \frac{- 12 + l - l ^{2} - 24 l + 64}{2}

二次方程组的解是:

x = - \frac{- 12 + l + l ^{2} - 24 l + 64}{2}, x = - \frac{- 12 + l - l ^{2} - 24 l + 64}{2}

作图

流行的例子

x^{2} + 1.4 = 3.6

12 h^{2} - h - 6 = 0

3 x^{2} - 5 = 34

6 x^{2} + x = 0

2 x + 3 = x^{2} + 3