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人気のある代数 >

(2x+1)^2-(2x+1)(x-3)=0

解

(2 x + 1)^{2} - (2 x + 1) (x - 3) = 0

解

x = - \frac{1}{2}, x = - 4

+1

十進法表記

x = - 0.5, x = - 4

解答ステップ

(2 x + 1)^{2} - (2 x + 1) (x - 3) = 0

拡張

(2 x + 1)^{2} - (2 x + 1) (x - 3) : 2 x^{2} + 9 x + 4

2 x^{2} + 9 x + 4 = 0

解くとthe二次式

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 \cdot 4}{2 \cdot 2}

9^{2} - 4 \cdot 2 \cdot 4 = 7

x_{1, 2} = \frac{- 9 \pm 7}{2 \cdot 2}

解を分離する

x_{1} = \frac{- 9 + 7}{2 \cdot 2}, x_{2} = \frac{- 9 - 7}{2 \cdot 2}

x = \frac{- 9 + 7}{2 \cdot 2} : - \frac{1}{2}

x = \frac{- 9 - 7}{2 \cdot 2} : - 4

二次equationの解:

x = - \frac{1}{2}, x = - 4

グラフ

人気の例

solvefor x,x^2-7x+6=0

so l v e f or x, x^{2} - 7 x + 6 = 0

(b+1)^2+b^2=(b+9)^2

(b + 1)^{2} + b^{2} = (b + 9)^{2}

4 x^{2} + 2 x = 6

5 x - x^{2} = 6

solvefor F,gb+Nb=2F^2

so l v e f or F, g b + N b = 2 F^{2}