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受欢迎的代数 >

5a^2+a-2=0

解答

5 a^{2} + a - 2 = 0

解答

a = \frac{- 1 + 41}{10}, a = \frac{- 1 - 41}{10}

+1

十进制

a = 0.54031 \dots, a = - 0.74031 \dots

求解步骤

5 a^{2} + a - 2 = 0

使用求根公式求解

a_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

1^{2} - 4 \cdot 5 (- 2) = 41

a_{1, 2} = \frac{- 1 \pm 41}{2 \cdot 5}

将解分隔开

a_{1} = \frac{- 1 + 41}{2 \cdot 5}, a_{2} = \frac{- 1 - 41}{2 \cdot 5}

a = \frac{- 1 + 41}{2 \cdot 5} : \frac{- 1 + 41}{10}

a = \frac{- 1 - 41}{2 \cdot 5} : \frac{- 1 - 41}{10}

二次方程组的解是:

a = \frac{- 1 + 41}{10}, a = \frac{- 1 - 41}{10}

作图

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