What are the solutions to the equation x(2x+1)=1 ?

The solutions to the equation x(2x+1)=1 are x= 1/2 ,x=-1

Find the zeros of x(2x+1)=1

The zeros of x(2x+1)=1 are x= 1/2 ,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x (2 x + 1) = 1

x = \frac{1}{2}, x = - 1

Decimal Notation

x = 0.5, x = - 1

Solution steps

x (2 x + 1) = 1

Expand

x (2 x + 1) : 2 x^{2} + x

2 x^{2} + x = 1

Move

1

to the left side

2 x^{2} + x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 1) = 3

x_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 3}{2 \cdot 2}, x_{2} = \frac{- 1 - 3}{2 \cdot 2}

x = \frac{- 1 + 3}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 1 - 3}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 1

a^{2} + 76 a + 72 = 0

- 2 x^{2} + 20 x = 0

x^{2} - 2 x - 5 = x + 5

x^{2} - 11 = 25

2 x + 8 = - x^{2}

What are the solutions to the equation x(2x+1)=1 ?
The solutions to the equation x(2x+1)=1 are x= 1/2 ,x=-1
Find the zeros of x(2x+1)=1
The zeros of x(2x+1)=1 are x= 1/2 ,x=-1