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受欢迎的代数 >

solvefor x,y=x^2+px+q

解答

求解

x, y = x^{2} + p x + q

解答

x = \frac{- p + p ^{2} - 4 ( q - y )}{2}, x = \frac{- p - p ^{2} - 4 ( q - y )}{2}

求解步骤

y = x^{2} + p x + q

交换两边

x^{2} + p x + q = y

将

y

para o lado esquerdo

x^{2} + p x + q - y = 0

使用求根公式求解

x_{1, 2} = \frac{- p \pm p ^{2} - 4 \cdot 1 \cdot ( q - y )}{2 \cdot 1}

化简

p^{2} - 4 \cdot 1 \cdot (q - y) : p^{2} - 4 (q - y)

x_{1, 2} = \frac{- p \pm p ^{2} - 4 ( q - y )}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- p + p ^{2} - 4 ( q - y )}{2 \cdot 1}, x_{2} = \frac{- p - p ^{2} - 4 ( q - y )}{2 \cdot 1}

x = \frac{- p + p ^{2} - 4 ( q - y )}{2 \cdot 1} : \frac{- p + p ^{2} - 4 ( q - y )}{2}

x = \frac{- p - p ^{2} - 4 ( q - y )}{2 \cdot 1} : \frac{- p - p ^{2} - 4 ( q - y )}{2}

二次方程组的解是:

x = \frac{- p + p ^{2} - 4 ( q - y )}{2}, x = \frac{- p - p ^{2} - 4 ( q - y )}{2}

作图

流行的例子

solvefor x,f(a+1)=4x^2-x+5

so l v e f or x, f (a + 1) = 4 x^{2} - x + 5

(x-5)^2+x(x+3)=25

(x - 5)^{2} + x (x + 3) = 25

5 x^{2} - 12 x - 8 = 0

x^{2} - 3 = 4 x + 2

2 (x - 1)^{2} - 8 = 0