What are the solutions to the equation 12x^2-20x+3=0 ?

The solutions to the equation 12x^2-20x+3=0 are x= 3/2 ,x= 1/6

Find the zeros of 12x^2-20x+3=0

The zeros of 12x^2-20x+3=0 are x= 3/2 ,x= 1/6

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12 x^{2} - 20 x + 3 = 0

x = \frac{3}{2}, x = \frac{1}{6}

Decimal Notation

x = 1.5, x = 0.16666 \dots

Solution steps

12 x^{2} - 20 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 12 \cdot 3}{2 \cdot 12}

(- 20)^{2} - 4 \cdot 12 \cdot 3 = 16

x_{1, 2} = \frac{- ( - 20 ) \pm 16}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 16}{2 \cdot 12}, x_{2} = \frac{- ( - 20 ) - 16}{2 \cdot 12}

x = \frac{- ( - 20 ) + 16}{2 \cdot 12} : \frac{3}{2}

x = \frac{- ( - 20 ) - 16}{2 \cdot 12} : \frac{1}{6}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = \frac{1}{6}

- 2 x^{2} + 3 x + 3 = 0

5 (x + 3)^{2} = 2

x, y = 3 - x^{2}

V = π r^{2} h, r

8 x^{2} - 6 x + 3 = 0

What are the solutions to the equation 12x^2-20x+3=0 ?
The solutions to the equation 12x^2-20x+3=0 are x= 3/2 ,x= 1/6
Find the zeros of 12x^2-20x+3=0
The zeros of 12x^2-20x+3=0 are x= 3/2 ,x= 1/6