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受欢迎的代数 >

solvefor x,f(x-2)=-3x^2-1

解答

求解

x, f (x - 2) = - 3 x^{2} - 1

解答

x = - \frac{f + f ^{2} + 12 ( - 1 + 2 f )}{6}, x = - \frac{f - f ^{2} + 12 ( - 1 + 2 f )}{6}

求解步骤

f (x - 2) = - 3 x^{2} - 1

展开

f (x - 2) : x f - 2 f

x f - 2 f = - 3 x^{2} - 1

交换两边

- 3 x^{2} - 1 = x f - 2 f

将

2 f

para o lado esquerdo

- 3 x^{2} - 1 + 2 f = x f

将

x f

para o lado esquerdo

- 3 x^{2} - 1 + 2 f - x f = 0

改写成标准形式

a x^{2} + b x + c = 0

- 3 x^{2} - f x - 1 + 2 f = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - f ) \pm ( - f ) ^{2} - 4 ( - 3 ) ( - 1 + 2 f )}{2 ( - 3 )}

化简

(- f)^{2} - 4 (- 3) (- 1 + 2 f) : f^{2} + 12 (- 1 + 2 f)

x_{1, 2} = \frac{- ( - f ) \pm f ^{2} + 12 ( - 1 + 2 f )}{2 ( - 3 )}

将解分隔开

x_{1} = \frac{- ( - f ) + f ^{2} + 12 ( - 1 + 2 f )}{2 ( - 3 )}, x_{2} = \frac{- ( - f ) - f ^{2} + 12 ( - 1 + 2 f )}{2 ( - 3 )}

x = \frac{- ( - f ) + f ^{2} + 12 ( - 1 + 2 f )}{2 ( - 3 )} : - \frac{f + f ^{2} + 12 ( - 1 + 2 f )}{6}

x = \frac{- ( - f ) - f ^{2} + 12 ( - 1 + 2 f )}{2 ( - 3 )} : - \frac{f - f ^{2} + 12 ( - 1 + 2 f )}{6}

二次方程组的解是:

x = - \frac{f + f ^{2} + 12 ( - 1 + 2 f )}{6}, x = - \frac{f - f ^{2} + 12 ( - 1 + 2 f )}{6}

作图

流行的例子

solvefor x,y(x^2-1)=2

so l v e f or x, y (x^{2} - 1) = 2

6 - 2 x^{2} = 6 x

x^{2} + 40 = - 14 x

x^{2} + 2 = 4 x

- (x - 6)^{2} + 6 = - 11