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受欢迎的代数 >

solvefor x,f(x-2)=x^2-3x+4

解答

求解

x, f (x - 2) = x^{2} - 3 x + 4

解答

x = \frac{3 + f + f ^{2} - 2 f - 7}{2}, x = \frac{3 + f - f ^{2} - 2 f - 7}{2}

求解步骤

f (x - 2) = x^{2} - 3 x + 4

展开

f (x - 2) : x f - 2 f

x f - 2 f = x^{2} - 3 x + 4

交换两边

x^{2} - 3 x + 4 = x f - 2 f

将

2 f

para o lado esquerdo

x^{2} - 3 x + 4 + 2 f = x f

将

x f

para o lado esquerdo

x^{2} - 3 x + 4 + 2 f - x f = 0

改写成标准形式

a x^{2} + b x + c = 0

x^{2} - (3 + f) x + 4 + 2 f = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 3 - f ) \pm ( - 3 - f ) ^{2} - 4 \cdot 1 \cdot ( 4 + 2 f )}{2 \cdot 1}

化简

(- 3 - f)^{2} - 4 \cdot 1 \cdot (4 + 2 f) : f^{2} - 2 f - 7

x_{1, 2} = \frac{- ( - 3 - f ) \pm f ^{2} - 2 f - 7}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( - 3 - f ) + f ^{2} - 2 f - 7}{2 \cdot 1}, x_{2} = \frac{- ( - 3 - f ) - f ^{2} - 2 f - 7}{2 \cdot 1}

x = \frac{- ( - 3 - f ) + f ^{2} - 2 f - 7}{2 \cdot 1} : \frac{3 + f + f ^{2} - 2 f - 7}{2}

x = \frac{- ( - 3 - f ) - f ^{2} - 2 f - 7}{2 \cdot 1} : \frac{3 + f - f ^{2} - 2 f - 7}{2}

二次方程组的解是:

x = \frac{3 + f + f ^{2} - 2 f - 7}{2}, x = \frac{3 + f - f ^{2} - 2 f - 7}{2}

作图

流行的例子

2 x^{2} + 3 x - 3 = 1

5 x^{2} - 9 x - 10 = 0

(4x-3)^2=(x+2)^2

(4 x - 3)^{2} = (x + 2)^{2}

9 x^{2} + 5 = 1

x^{2} + 6 x - 150 = 0