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受欢迎的代数 >

solvefor x,36x^2-12x+1=k^2

解答

x, 36 x^{2} - 12 x + 1 = k^{2}

解答

x = \frac{1 + k}{6}, x = \frac{1 - k}{6}

求解步骤

36 x^{2} - 12 x + 1 = k^{2}

将

k^{2}

para o lado esquerdo

36 x^{2} - 12 x + 1 - k^{2} = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 36 ( 1 - k ^{2} )}{2 \cdot 36}

化简

(- 12)^{2} - 4 \cdot 36 (1 - k^{2}) : 12 k

x_{1, 2} = \frac{- ( - 12 ) \pm 12 k}{2 \cdot 36}

将解分隔开

x_{1} = \frac{- ( - 12 ) + 12 k}{2 \cdot 36}, x_{2} = \frac{- ( - 12 ) - 12 k}{2 \cdot 36}

x = \frac{- ( - 12 ) + 12 k}{2 \cdot 36} : \frac{1 + k}{6}

x = \frac{- ( - 12 ) - 12 k}{2 \cdot 36} : \frac{1 - k}{6}

二次方程组的解是:

x = \frac{1 + k}{6}, x = \frac{1 - k}{6}

作图

流行的例子

x^{2} - 11 + 24 = 0

solvefor y,x+(y-7)^2=0

so l v e f or y, x + (y - 7)^{2} = 0

2 x^{2} + 3 x - 44 = 0

2 x^{2} - 20 x - 24 = 0

solvefor x,1-6x+9x^2=t

so l v e f or x, 1 - 6 x + 9 x^{2} = t