What are the solutions to the equation 3x^2+10x-9=0 ?

The solutions to the equation 3x^2+10x-9=0 are x=(-5+2sqrt(13))/3 ,x=-(5+2sqrt(13))/3

Find the zeros of 3x^2+10x-9=0

The zeros of 3x^2+10x-9=0 are x=(-5+2sqrt(13))/3 ,x=-(5+2sqrt(13))/3

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3 x^{2} + 10 x - 9 = 0

x = \frac{- 5 + 2 13}{3}, x = - \frac{5 + 2 13}{3}

Decimal Notation

x = 0.73703 \dots, x = - 4.07036 \dots

Solution steps

3 x^{2} + 10 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 9) = 413

x_{1, 2} = \frac{- 10 \pm 4 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 4 13}{2 \cdot 3}, x_{2} = \frac{- 10 - 4 13}{2 \cdot 3}

x = \frac{- 10 + 4 13}{2 \cdot 3} : \frac{- 5 + 2 13}{3}

x = \frac{- 10 - 4 13}{2 \cdot 3} : - \frac{5 + 2 13}{3}

The solutions to the quadratic equation are:

x = \frac{- 5 + 2 13}{3}, x = - \frac{5 + 2 13}{3}

x^{2} = 92

x^{2} = 73

x, x^{2} + 8 x + 5 = 0

3 x^{2} - 2 x = x^{2} + 4

2 x^{2} + 6 x = - 8

What are the solutions to the equation 3x^2+10x-9=0 ?
The solutions to the equation 3x^2+10x-9=0 are x=(-5+2sqrt(13))/3 ,x=-(5+2sqrt(13))/3
Find the zeros of 3x^2+10x-9=0
The zeros of 3x^2+10x-9=0 are x=(-5+2sqrt(13))/3 ,x=-(5+2sqrt(13))/3