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受欢迎的代数 >

x^2+(2a-1)x-2a=0

解答

x^{2} + (2 a - 1) x - 2 a = 0

解答

x = 1, x = - 2 a

求解步骤

x^{2} + (2 a - 1) x - 2 a = 0

使用求根公式求解

x_{1, 2} = \frac{- ( 2 a - 1 ) \pm ( 2 a - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 a )}{2 \cdot 1}

化简

(2 a - 1)^{2} - 4 \cdot 1 \cdot (- 2 a) : 2 a + 1

x_{1, 2} = \frac{- ( 2 a - 1 ) \pm ( 2 a + 1 )}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( 2 a - 1 ) + 2 a + 1}{2 \cdot 1}, x_{2} = \frac{- ( 2 a - 1 ) - ( 2 a + 1 )}{2 \cdot 1}

x = \frac{- ( 2 a - 1 ) + 2 a + 1}{2 \cdot 1} : 1

x = \frac{- ( 2 a - 1 ) - ( 2 a + 1 )}{2 \cdot 1} : - 2 a

二次方程组的解是:

x = 1, x = - 2 a

作图

流行的例子

4 m^{2} + 10 m + 5 = - m

3 x^{2} + 5 = 4 x^{2} + 3

y^{2} - 2 y + 17 = 0

2(x-0.1)(2x-1.5)=0

2 (x - 0.1) (2 x - 1.5) = 0

- y^{2} - y + 2 = 0