What are the solutions to the equation 4x^2+17x+19=0 ?

The solutions to the equation 4x^2+17x+19=0 are x=-17/8+i(sqrt(15))/8 ,x=-17/8-i(sqrt(15))/8

Find the zeros of 4x^2+17x+19=0

The zeros of 4x^2+17x+19=0 are x=-17/8+i(sqrt(15))/8 ,x=-17/8-i(sqrt(15))/8

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4 x^{2} + 17 x + 19 = 0

x = - \frac{17}{8} + i \frac{15}{8}, x = - \frac{17}{8} - i \frac{15}{8}

Solution steps

4 x^{2} + 17 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 4 \cdot 19}{2 \cdot 4}

Simplify

1 7^{2} - 4 \cdot 4 \cdot 19 : 15 i

x_{1, 2} = \frac{- 17 \pm 15 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 17 + 15 i}{2 \cdot 4}, x_{2} = \frac{- 17 - 15 i}{2 \cdot 4}

x = \frac{- 17 + 15 i}{2 \cdot 4} : - \frac{17}{8} + i \frac{15}{8}

x = \frac{- 17 - 15 i}{2 \cdot 4} : - \frac{17}{8} - i \frac{15}{8}

The solutions to the quadratic equation are:

x = - \frac{17}{8} + i \frac{15}{8}, x = - \frac{17}{8} - i \frac{15}{8}

2 x^{2} + 9 x = 18

- 4 a^{2} + 144 = 0

a = \frac{1}{4} 3 a^{2}

4 b^{2} = 30 + 7 (6 + 4)

x^{2} - 5 x + 3 = - 8 x + 1

What are the solutions to the equation 4x^2+17x+19=0 ?
The solutions to the equation 4x^2+17x+19=0 are x=-17/8+i(sqrt(15))/8 ,x=-17/8-i(sqrt(15))/8
Find the zeros of 4x^2+17x+19=0
The zeros of 4x^2+17x+19=0 are x=-17/8+i(sqrt(15))/8 ,x=-17/8-i(sqrt(15))/8