What are the solutions to the equation -4x^2=12x ?

The solutions to the equation -4x^2=12x are x=0,x=-3

Find the zeros of -4x^2=12x

The zeros of -4x^2=12x are x=0,x=-3

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- 4 x^{2} = 12 x

x = 0, x = - 3

Solution steps

- 4 x^{2} = 12 x

Move

12 x

to the left side

- 4 x^{2} - 12 x = 0

Factor

- 4 x^{2} - 12 x : - 4 x (x + 3)

- 4 x (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 3 = 0

Solve

x + 3 = 0 : x = - 3

The solutions to the quadratic equation are:

x = 0, x = - 3

\frac{1}{2} x^{2} = \frac{1}{4}

3 x^{2} - 15 x + 6 = 0

x (x - 6) + 8 = 0

w^{2} + 7 w + 6 = 0

a, (a + b)^{2} = 64

What are the solutions to the equation -4x^2=12x ?
The solutions to the equation -4x^2=12x are x=0,x=-3
Find the zeros of -4x^2=12x
The zeros of -4x^2=12x are x=0,x=-3