What are the solutions to the equation 5x^2-4x-10=0 ?

The solutions to the equation 5x^2-4x-10=0 are x=(2+3sqrt(6))/5 ,x=(2-3sqrt(6))/5

Find the zeros of 5x^2-4x-10=0

The zeros of 5x^2-4x-10=0 are x=(2+3sqrt(6))/5 ,x=(2-3sqrt(6))/5

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5 x^{2} - 4 x - 10 = 0

x = \frac{2 + 3 6}{5}, x = \frac{2 - 3 6}{5}

Decimal Notation

x = 1.86969 \dots, x = - 1.06969 \dots

Solution steps

5 x^{2} - 4 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 5 ( - 10 )}{2 \cdot 5}

(- 4)^{2} - 4 \cdot 5 (- 10) = 66

x_{1, 2} = \frac{- ( - 4 ) \pm 6 6}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6 6}{2 \cdot 5}, x_{2} = \frac{- ( - 4 ) - 6 6}{2 \cdot 5}

x = \frac{- ( - 4 ) + 6 6}{2 \cdot 5} : \frac{2 + 3 6}{5}

x = \frac{- ( - 4 ) - 6 6}{2 \cdot 5} : \frac{2 - 3 6}{5}

The solutions to the quadratic equation are:

x = \frac{2 + 3 6}{5}, x = \frac{2 - 3 6}{5}

2 x^{2} = 6 x - 6

12 x^{2} - 72 x - 84 = 0

n^{2} - 159 = 10

x^{2} + 18 = - 6 x

- 4 x^{2} = - 8

What are the solutions to the equation 5x^2-4x-10=0 ?
The solutions to the equation 5x^2-4x-10=0 are x=(2+3sqrt(6))/5 ,x=(2-3sqrt(6))/5
Find the zeros of 5x^2-4x-10=0
The zeros of 5x^2-4x-10=0 are x=(2+3sqrt(6))/5 ,x=(2-3sqrt(6))/5