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受欢迎的代数 >

3q^2-136q+1300=0

解答

3 q^{2} - 136 q + 1300 = 0

解答

q = \frac{2 ( 34 + 181 )}{3}, q = \frac{2 ( 34 - 181 )}{3}

+1

十进制

q = 31.63574 \dots, q = 13.69758 \dots

求解步骤

3 q^{2} - 136 q + 1300 = 0

使用求根公式求解

q_{1, 2} = \frac{- ( - 136 ) \pm ( - 136 ) ^{2} - 4 \cdot 3 \cdot 1300}{2 \cdot 3}

(- 136)^{2} - 4 \cdot 3 \cdot 1300 = 4181

q_{1, 2} = \frac{- ( - 136 ) \pm 4 181}{2 \cdot 3}

将解分隔开

q_{1} = \frac{- ( - 136 ) + 4 181}{2 \cdot 3}, q_{2} = \frac{- ( - 136 ) - 4 181}{2 \cdot 3}

q = \frac{- ( - 136 ) + 4 181}{2 \cdot 3} : \frac{2 ( 34 + 181 )}{3}

q = \frac{- ( - 136 ) - 4 181}{2 \cdot 3} : \frac{2 ( 34 - 181 )}{3}

二次方程组的解是:

q = \frac{2 ( 34 + 181 )}{3}, q = \frac{2 ( 34 - 181 )}{3}

作图

流行的例子

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