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受欢迎的代数 >

solvefor x,f(x+1)=4x^2+3x-2

解答

求解

x, f (x + 1) = 4 x^{2} + 3 x - 2

解答

x = \frac{- 3 + f + f ^{2} + 10 f + 41}{8}, x = \frac{- 3 + f - f ^{2} + 10 f + 41}{8}

求解步骤

f (x + 1) = 4 x^{2} + 3 x - 2

展开

f (x + 1) : x f + f

x f + f = 4 x^{2} + 3 x - 2

交换两边

4 x^{2} + 3 x - 2 = x f + f

将

f

para o lado esquerdo

4 x^{2} + 3 x - 2 - f = x f

将

x f

para o lado esquerdo

4 x^{2} + 3 x - 2 - f - x f = 0

改写成标准形式

a x^{2} + b x + c = 0

4 x^{2} + (3 - f) x - 2 - f = 0

使用求根公式求解

x_{1, 2} = \frac{- ( 3 - f ) \pm ( 3 - f ) ^{2} - 4 \cdot 4 ( - 2 - f )}{2 \cdot 4}

化简

(3 - f)^{2} - 4 \cdot 4 (- 2 - f) : f^{2} + 10 f + 41

x_{1, 2} = \frac{- ( 3 - f ) \pm f ^{2} + 10 f + 41}{2 \cdot 4}

将解分隔开

x_{1} = \frac{- ( 3 - f ) + f ^{2} + 10 f + 41}{2 \cdot 4}, x_{2} = \frac{- ( 3 - f ) - f ^{2} + 10 f + 41}{2 \cdot 4}

x = \frac{- ( 3 - f ) + f ^{2} + 10 f + 41}{2 \cdot 4} : \frac{- 3 + f + f ^{2} + 10 f + 41}{8}

x = \frac{- ( 3 - f ) - f ^{2} + 10 f + 41}{2 \cdot 4} : \frac{- 3 + f - f ^{2} + 10 f + 41}{8}

二次方程组的解是:

x = \frac{- 3 + f + f ^{2} + 10 f + 41}{8}, x = \frac{- 3 + f - f ^{2} + 10 f + 41}{8}

作图

流行的例子

36 v^{2} + 2 = 6

x (x - 2) = - 1

16 x^{2} + 25 = - 40 x

x^{2} - 11 x - 2 = 0

r^{2} - 49 = 0