(-a)^2-4(1)(-2a)=0

解答

(- a)^{2} - 4 (1) (- 2 a) = 0

a = 0, a = - 8

求解步骤

(- a)^{2} - 4 (1) (- 2 a) = 0

展开

(- a)^{2} - 4 (1) (- 2 a) : a^{2} + 8 a

a^{2} + 8 a = 0

使用求根公式求解

a_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 0 = 8

a_{1, 2} = \frac{- 8 \pm 8}{2 \cdot 1}

将解分隔开

a_{1} = \frac{- 8 + 8}{2 \cdot 1}, a_{2} = \frac{- 8 - 8}{2 \cdot 1}

a = \frac{- 8 + 8}{2 \cdot 1} : 0

a = \frac{- 8 - 8}{2 \cdot 1} : - 8

二次方程组的解是:

a = 0, a = - 8

so l v e f or v, v^{2} = u^{2} + 2 a s

so l v e f or x, (x - 0)^{2} = 4 p (y - 10)

so l v e f or x, f (x + 1) = - x^{2} + x + 1

so l v e f or x, x^{2} - 3 x^{2} y = C

3 k^{2} - 96 k + 92 = 0