What are the solutions to the equation (2x-3)^2=5 ?

The solutions to the equation (2x-3)^2=5 are x=(sqrt(5)+3)/2 ,x=(-sqrt(5)+3)/2

Find the zeros of (2x-3)^2=5

The zeros of (2x-3)^2=5 are x=(sqrt(5)+3)/2 ,x=(-sqrt(5)+3)/2

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(2 x - 3)^{2} = 5

x = \frac{5 + 3}{2}, x = \frac{- 5 + 3}{2}

Decimal Notation

x = 2.61803 \dots, x = 0.38196 \dots

Solution steps

(2 x - 3)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 3 = 5 : x = \frac{5 + 3}{2}

Solve

2 x - 3 = - 5 : x = \frac{- 5 + 3}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 3}{2}, x = \frac{- 5 + 3}{2}

- 3 x^{2} + 3 x + 1 = 0

7^{2} + x^{2} = 1 3^{2}

p^{2} + 0.8 p + 0.16 = 1

(x + 4)^{2} + (x - 3)^{2} = (x - 5)^{2}

z (z + 5) = - 6

What are the solutions to the equation (2x-3)^2=5 ?
The solutions to the equation (2x-3)^2=5 are x=(sqrt(5)+3)/2 ,x=(-sqrt(5)+3)/2
Find the zeros of (2x-3)^2=5
The zeros of (2x-3)^2=5 are x=(sqrt(5)+3)/2 ,x=(-sqrt(5)+3)/2