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受欢迎的代数 >

(m-1)x^2-9=3mx

解答

(m - 1) x^{2} - 9 = 3 m x

解答

x = \frac{3 m + 3 m ^{2} + 4 ( - 1 + m )}{2 ( m - 1 )}, x = \frac{3 m - 3 m ^{2} + 4 ( - 1 + m )}{2 ( m - 1 )}; m \neq = 1

求解步骤

(m - 1) x^{2} - 9 = 3 m x

将

3 m x

para o lado esquerdo

(m - 1) x^{2} - 9 - 3 m x = 0

改写成标准形式

a x^{2} + b x + c = 0

(m - 1) x^{2} - 3 m x - 9 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 3 m ) \pm ( - 3 m ) ^{2} - 4 ( m - 1 ) ( - 9 )}{2 ( m - 1 )}

化简

(- 3 m)^{2} - 4 (m - 1) (- 9) : 3 m^{2} + 4 (- 1 + m)

x_{1, 2} = \frac{- ( - 3 m ) \pm 3 m ^{2} + 4 ( - 1 + m )}{2 ( m - 1 )}; m \neq = 1

将解分隔开

x_{1} = \frac{- ( - 3 m ) + 3 m ^{2} + 4 ( - 1 + m )}{2 ( m - 1 )}, x_{2} = \frac{- ( - 3 m ) - 3 m ^{2} + 4 ( - 1 + m )}{2 ( m - 1 )}

x = \frac{- ( - 3 m ) + 3 m ^{2} + 4 ( - 1 + m )}{2 ( m - 1 )} : \frac{3 m + 3 m ^{2} + 4 ( - 1 + m )}{2 ( m - 1 )}

x = \frac{- ( - 3 m ) - 3 m ^{2} + 4 ( - 1 + m )}{2 ( m - 1 )} : \frac{3 m - 3 m ^{2} + 4 ( - 1 + m )}{2 ( m - 1 )}

二次方程组的解是:

x = \frac{3 m + 3 m ^{2} + 4 ( - 1 + m )}{2 ( m - 1 )}, x = \frac{3 m - 3 m ^{2} + 4 ( - 1 + m )}{2 ( m - 1 )}; m \neq = 1

作图

流行的例子

x^{2} + 2 x - 1 = 1

x^{2} - 9 x = 18

x^{2} - 9 x = - 2

2 u^{2} + 5 u = - 3

-16t^2+40t-24=0

- 16 t^{2} + 40 t - 24 = 0