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受欢迎的代数 >

t=-3.3t^2+5t+6

解答

t = - 3.3 t^{2} + 5 t + 6

解答

t = - \frac{2 ( 595 - 10 )}{33}, t = \frac{2 ( 10 + 595 )}{33}

+1

十进制

t = - 0.87228 \dots, t = 2.08440 \dots

求解步骤

t = - 3.3 t^{2} + 5 t + 6

在两边乘以

10

t \cdot 10 = - 33 t^{2} + 50 t + 60

交换两边

- 33 t^{2} + 50 t + 60 = t \cdot 10

将

t 10

para o lado esquerdo

- 33 t^{2} + 40 t + 60 = 0

使用求根公式求解

t_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 ( - 33 ) \cdot 60}{2 ( - 33 )}

4 0^{2} - 4 (- 33) \cdot 60 = 4595

t_{1, 2} = \frac{- 40 \pm 4 595}{2 ( - 33 )}

将解分隔开

t_{1} = \frac{- 40 + 4 595}{2 ( - 33 )}, t_{2} = \frac{- 40 - 4 595}{2 ( - 33 )}

t = \frac{- 40 + 4 595}{2 ( - 33 )} : - \frac{2 ( 595 - 10 )}{33}

t = \frac{- 40 - 4 595}{2 ( - 33 )} : \frac{2 ( 10 + 595 )}{33}

二次方程组的解是:

t = - \frac{2 ( 595 - 10 )}{33}, t = \frac{2 ( 10 + 595 )}{33}

作图

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