-5x^2+125x=0

解

- 5 x^{2} + 125 x = 0

x = 0, x = 25

解答ステップ

- 5 x^{2} + 125 x = 0

解くとthe二次式

x_{1, 2} = \frac{- 125 \pm 12 5 ^{2} - 4 ( - 5 ) \cdot 0}{2 ( - 5 )}

12 5^{2} - 4 (- 5) \cdot 0 = 125

x_{1, 2} = \frac{- 125 \pm 125}{2 ( - 5 )}

解を分離する

x_{1} = \frac{- 125 + 125}{2 ( - 5 )}, x_{2} = \frac{- 125 - 125}{2 ( - 5 )}

x = \frac{- 125 + 125}{2 ( - 5 )} : 0

x = \frac{- 125 - 125}{2 ( - 5 )} : 25

二次equationの解:

x = 0, x = 25