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受欢迎的代数 >

3b^2+9b-9=0

解答

3 b^{2} + 9 b - 9 = 0

解答

b = \frac{- 3 + 21}{2}, b = - \frac{3 + 21}{2}

+1

十进制

b = 0.79128 \dots, b = - 3.79128 \dots

求解步骤

3 b^{2} + 9 b - 9 = 0

使用求根公式求解

b_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

9^{2} - 4 \cdot 3 (- 9) = 321

b_{1, 2} = \frac{- 9 \pm 3 21}{2 \cdot 3}

将解分隔开

b_{1} = \frac{- 9 + 3 21}{2 \cdot 3}, b_{2} = \frac{- 9 - 3 21}{2 \cdot 3}

b = \frac{- 9 + 3 21}{2 \cdot 3} : \frac{- 3 + 21}{2}

b = \frac{- 9 - 3 21}{2 \cdot 3} : - \frac{3 + 21}{2}

二次方程组的解是:

b = \frac{- 3 + 21}{2}, b = - \frac{3 + 21}{2}

作图

流行的例子

21 - 20 x - x^{2} = 0

5 x^{2} - 16 x - 16 = 0

solvefor x,y^2+x^2=z^2

so l v e f or x, y^{2} + x^{2} = z^{2}

xc(x+2)-5=b(x-3)

x c (x + 2) - 5 = b (x - 3)

0 = - 2 x^{2} + 4 x