-5x^2+525x-2500=0

解

- 5 x^{2} + 525 x - 2500 = 0

x = 5, x = 100

解答ステップ

- 5 x^{2} + 525 x - 2500 = 0

解くとthe二次式

x_{1, 2} = \frac{- 525 \pm 52 5 ^{2} - 4 ( - 5 ) ( - 2500 )}{2 ( - 5 )}

52 5^{2} - 4 (- 5) (- 2500) = 475

x_{1, 2} = \frac{- 525 \pm 475}{2 ( - 5 )}

解を分離する

x_{1} = \frac{- 525 + 475}{2 ( - 5 )}, x_{2} = \frac{- 525 - 475}{2 ( - 5 )}

x = \frac{- 525 + 475}{2 ( - 5 )} : 5

x = \frac{- 525 - 475}{2 ( - 5 )} : 100

二次equationの解:

x = 5, x = 100