因式分解 9p^2+6p+1-q^2

解答

因式分解

9 p^{2} + 6 p + 1 - q^{2}

(3 p + 1 + q) (3 p + 1 - q)

求解步骤

9 p^{2} + 6 p + 1 - q^{2}

因式分解

9 p^{2} + 6 p + 1 : (3 p + 1)^{2}

= (3 p + 1)^{2} - q^{2}

使用平方差公式:

x^{2} - y^{2} = (x + y) (x - y)

(3 p + 1)^{2} - q^{2} = ((3 p + 1) + q) ((3 p + 1) - q)

= ((3 p + 1) + q) ((3 p + 1) - q)

使用法则:

(a) = a

(3 p + 1) = 3 p + 1

= (3 p + 1 + q) (3 p + 1 - q)

f a c t or 5 a + 15

f a c t or 3 x^{4} - 16 x^{3} + 14 x^{2} + 24 x - 9

3 x^{2} + 3 x - 6 = 0

s im pl i f y 4 u^{7}

x^{2} - 4 x + 23 = 0