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受欢迎的代数 >

192=-16t^2+112t

解答

192 = - 16 t^{2} + 112 t

解答

t = 3, t = 4

求解步骤

192 = - 16 t^{2} + 112 t

交换两边

- 16 t^{2} + 112 t = 192

将

192

para o lado esquerdo

- 16 t^{2} + 112 t - 192 = 0

使用求根公式求解

t_{1, 2} = \frac{- 112 \pm 11 2 ^{2} - 4 ( - 16 ) ( - 192 )}{2 ( - 16 )}

11 2^{2} - 4 (- 16) (- 192) = 16

t_{1, 2} = \frac{- 112 \pm 16}{2 ( - 16 )}

将解分隔开

t_{1} = \frac{- 112 + 16}{2 ( - 16 )}, t_{2} = \frac{- 112 - 16}{2 ( - 16 )}

t = \frac{- 112 + 16}{2 ( - 16 )} : 3

t = \frac{- 112 - 16}{2 ( - 16 )} : 4

二次方程组的解是:

t = 3, t = 4

作图

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