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受欢迎的代数 >

-29=4z-17z^2+13z^2

解答

- 29 = 4 z - 17 z^{2} + 13 z^{2}

解答

z = - \frac{- 1 + 30}{2}, z = \frac{1 + 30}{2}

+1

十进制

z = - 2.23861 \dots, z = 3.23861 \dots

求解步骤

- 29 = 4 z - 17 z^{2} + 13 z^{2}

整理后得

- 29 = 4 z - 4 z^{2}

交换两边

4 z - 4 z^{2} = - 29

将

29

para o lado esquerdo

4 z - 4 z^{2} + 29 = 0

改写成标准形式

a x^{2} + b x + c = 0

- 4 z^{2} + 4 z + 29 = 0

使用求根公式求解

z_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 4 ) \cdot 29}{2 ( - 4 )}

4^{2} - 4 (- 4) \cdot 29 = 430

z_{1, 2} = \frac{- 4 \pm 4 30}{2 ( - 4 )}

将解分隔开

z_{1} = \frac{- 4 + 4 30}{2 ( - 4 )}, z_{2} = \frac{- 4 - 4 30}{2 ( - 4 )}

z = \frac{- 4 + 4 30}{2 ( - 4 )} : - \frac{- 1 + 30}{2}

z = \frac{- 4 - 4 30}{2 ( - 4 )} : \frac{1 + 30}{2}

二次方程组的解是:

z = - \frac{- 1 + 30}{2}, z = \frac{1 + 30}{2}

作图

流行的例子

49 s^{2} + 70 s = - 25

2 x^{2} - 30 x + 100 = 0

x^{2} - 75 x + 20 = 0

2 (x - 4) (x - 8) = - 1

0 = 2 x^{2} + 7 x - 15