What are the solutions to the equation 5x^2+23x=13x-10 ?

The solutions to the equation 5x^2+23x=13x-10 are x=-1+i,x=-1-i

Find the zeros of 5x^2+23x=13x-10

The zeros of 5x^2+23x=13x-10 are x=-1+i,x=-1-i

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5 x^{2} + 23 x = 13 x - 10

x = - 1 + i, x = - 1 - i

Solution steps

5 x^{2} + 23 x = 13 x - 10

Move

10

to the left side

5 x^{2} + 23 x + 10 = 13 x

Move

13 x

to the left side

5 x^{2} + 10 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 5 \cdot 10}{2 \cdot 5}

Simplify

1 0^{2} - 4 \cdot 5 \cdot 10 : 10 i

x_{1, 2} = \frac{- 10 \pm 10 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 10 + 10 i}{2 \cdot 5}, x_{2} = \frac{- 10 - 10 i}{2 \cdot 5}

x = \frac{- 10 + 10 i}{2 \cdot 5} : - 1 + i

x = \frac{- 10 - 10 i}{2 \cdot 5} : - 1 - i

The solutions to the quadratic equation are:

x = - 1 + i, x = - 1 - i

9 x^{2} + 8 x - 5 = 0

(x - 4)^{2} - 144 = 0

- X^{2} + 5 X - 100 = 0

x^{2} + 15 x + 18 = 0

(x - 2)^{2} + (1 - 3 x)^{2} = 5

What are the solutions to the equation 5x^2+23x=13x-10 ?
The solutions to the equation 5x^2+23x=13x-10 are x=-1+i,x=-1-i
Find the zeros of 5x^2+23x=13x-10
The zeros of 5x^2+23x=13x-10 are x=-1+i,x=-1-i