(2x^2)/(x+1)-x+1=0

Lösung

\frac{2 x ^{2}}{x + 1} - x + 1 = 0

x = i, x = - i

Schritte zur Lösung

\frac{2 x ^{2}}{x + 1} - x + 1 = 0

Multipliziere beide Seiten mit

x + 1

2 x^{2} - x (x + 1) + x + 1 = 0

Löse

2 x^{2} - x (x + 1) + x + 1 = 0 : x = i, x = - i

x = i, x = - i

\frac{1}{5 ( k - 3 )} = \frac{3}{4}

\frac{r}{3 r} = 12

\frac{1}{2 x} = \frac{4}{3}

\frac{y + 2}{y} = \frac{5}{3}

\frac{6}{x - 8} = \frac{2}{x + 6}