4/z =(3z)/(z-3)

Lösung

\frac{4}{z} = \frac{3 z}{z - 3}

z = \frac{2}{3} + i \frac{4 2}{3}, z = \frac{2}{3} - i \frac{4 2}{3}

Schritte zur Lösung

\frac{4}{z} = \frac{3 z}{z - 3}

Kreuzmultiplizieren

4 (z - 3) = 3 z^{2}

Löse

4 (z - 3) = 3 z^{2} : z = \frac{2}{3} + i \frac{4 2}{3}, z = \frac{2}{3} - i \frac{4 2}{3}

z = \frac{2}{3} + i \frac{4 2}{3}, z = \frac{2}{3} - i \frac{4 2}{3}

\frac{x}{x + 1} = \frac{4}{3}

x + \frac{1}{x} = - 4

\frac{1}{8} = \frac{1}{1 - 6 x}

so l v e f or I = \frac{PN}{RN + A}, N

\frac{- 2}{x} = \frac{7}{x - 9} - 1