solvefor b,2=Q+f/b

解答

求解

b, 2 = Q + \frac{f}{b}

b = \frac{f}{2 - Q}; Q \neq = 2

求解步骤

2 = Q + \frac{f}{b}

将

Q

para o lado esquerdo

2 - Q = \frac{f}{b}

在两边乘以

b

2 b - Q b = f

分解

2 b - Q b : b (2 - Q)

b (2 - Q) = f

两边除以

2 - Q; Q \neq = 2

b = \frac{f}{2 - Q}; Q \neq = 2

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