solvefor d,m= g/d+3

解答

求解

d, m = \frac{g}{d} + 3

d = \frac{g}{m - 3}; m \neq = 3

求解步骤

m = \frac{g}{d} + 3

将

3

para o lado esquerdo

m - 3 = \frac{g}{d}

在两边乘以

d

m d - 3 d = g

分解

m d - 3 d : d (m - 3)

d (m - 3) = g

两边除以

m - 3; m \neq = 3

d = \frac{g}{m - 3}; m \neq = 3

\frac{x - 6}{x - 4} = \frac{- 5}{x}

\frac{( n + 2 ) !}{( n - 1 ) !} = 30 n

\frac{( 2 x + 1 ) ( x - 1 )}{( x + 1 )} = 0

\frac{6}{12} = \frac{2}{n}

so l v e f or a, hb + 5 = \frac{- b}{2 a}