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受欢迎的代数 >

solvefor x,t= 5/(x+3)-1

解答

求解

x, t = \frac{5}{x + 3} - 1

解答

x = \frac{2 - 3 t}{t + 1}; t \neq = - 1

求解步骤

t = \frac{5}{x + 3} - 1

将

1

para o lado esquerdo

t + 1 = \frac{5}{x + 3}

在两边乘以

x + 3

t (x + 3) + x + 3 = 5

将

3

到右边

t (x + 3) + x = 2

乘开

t (x + 3) : x t + 3 t

x t + 3 t + x = 2

将

3 t

到右边

x t + x = 2 - 3 t

分解

x t + x : x (t + 1)

x (t + 1) = 2 - 3 t

两边除以

t + 1; t \neq = - 1

x = \frac{2 - 3 t}{t + 1}; t \neq = - 1

作图

流行的例子

((-7))/x =(2x)/8

\frac{( - 7 )}{x} = \frac{2 x}{8}

solvefor B,0.3= B/(A+2B)

so l v e f or B, 0.3 = \frac{B}{A + 2 B}

(x^3-8)/(x^2+1)=0

\frac{x ^{3} - 8}{x ^{2} + 1} = 0

1.37 = \frac{12.85}{x}

1/(x-1)-2/(x-4)=1

\frac{1}{x - 1} - \frac{2}{x - 4} = 1