(q)=((30q-10)^2)/(3q-5)

解答

(q) = \frac{( 30 q - 10 ) ^{2}}{3 q - 5}

q = \frac{595}{1794} + i \frac{5 191}{1794}, q = \frac{595}{1794} - i \frac{5 191}{1794}

求解步骤

(q) = \frac{( 30 q - 10 ) ^{2}}{3 q - 5}

在两边乘以

3 q - 5

q (3 q - 5) = (30 q - 10)^{2}

解

q (3 q - 5) = (30 q - 10)^{2} : q = \frac{595}{1794} + i \frac{5 191}{1794}, q = \frac{595}{1794} - i \frac{5 191}{1794}

q = \frac{595}{1794} + i \frac{5 191}{1794}, q = \frac{595}{1794} - i \frac{5 191}{1794}

so l v e f or x, f (x)^{- 1} = x^{2}

x^{- 1} = 9

\frac{2}{x - 5} + \frac{3}{x - 4} = 2

4 π x - \frac{2000}{x ^{2}} = 0

7 x^{- 2} - 33 x^{- 1} + 20 = 0