(64)/x (1+x+x^2)=56

解

\frac{64}{x} (1 + x + x^{2}) = 56

x = - \frac{1}{16} + i \frac{255}{16}, x = - \frac{1}{16} - i \frac{255}{16}

解答ステップ

\frac{64}{x} (1 + x + x^{2}) = 56

簡素化

\frac{64}{x} (1 + x + x^{2}) : \frac{64 ( 1 + x + x ^{2} )}{x}

\frac{64 ( 1 + x + x ^{2} )}{x} = 56

以下で両辺を乗じる:

x

64 (1 + x + x^{2}) = 56 x

解く

64 (1 + x + x^{2}) = 56 x : x = - \frac{1}{16} + i \frac{255}{16}, x = - \frac{1}{16} - i \frac{255}{16}

x = - \frac{1}{16} + i \frac{255}{16}, x = - \frac{1}{16} - i \frac{255}{16}