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受欢迎的代数 >

(ax^3+2x)/(x+1)=x^2-x

解答

\frac{a x ^{3} + 2 x}{x + 1} = x^{2} - x

解答

x = 0, x = i \frac{3}{- 1 + a}, x = - i \frac{3}{- 1 + a}; a \neq = 1

求解步骤

\frac{a x ^{3} + 2 x}{x + 1} = x^{2} - x

在两边乘以

x + 1

a x^{3} + 2 x = x^{2} (x + 1) - x (x + 1)

解

a x^{3} + 2 x = x^{2} (x + 1) - x (x + 1) : x = 0, x = i \frac{3}{- 1 + a}, x = - i \frac{3}{- 1 + a}; a \neq = 1

x = 0, x = i \frac{3}{- 1 + a}, x = - i \frac{3}{- 1 + a}; a \neq = 1

验证解

找到无定义的点（奇点）:

x = - 1

将不在定义域的点与解相综合:

x = 0, x = i \frac{3}{- 1 + a}, x = - i \frac{3}{- 1 + a}; a \neq = 1

作图

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