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Beliebt Algebra >

b(x)= 1/(x+3),[1,1+h(x)]

Lösung

b (x) = \frac{1}{x + 3}, [1, 1 + h (x)]

Lösung

x = \frac{- 3 b + 9 b ^{2} + 4 b}{2 b}, x = \frac{- 3 b - 9 b ^{2} + 4 b}{2 b}; b \neq = 0

Schritte zur Lösung

b (x) = \frac{1}{x + 3}

Multipliziere beide Seiten mit

x + 3

b x (x + 3) = 1

Löse

b x (x + 3) = 1 : x = \frac{- 3 b + 9 b ^{2} + 4 b}{2 b}, x = \frac{- 3 b - 9 b ^{2} + 4 b}{2 b}; b \neq = 0

x = \frac{- 3 b + 9 b ^{2} + 4 b}{2 b}, x = \frac{- 3 b - 9 b ^{2} + 4 b}{2 b}; b \neq = 0

Graph

Beliebte Beispiele

(x^2-10x)/((x-5)^2)=0

\frac{x ^{2} - 10 x}{( x - 5 ) ^{2}} = 0

solvefor x,y=((x+8))/(x-9)

so l v e f or x, y = \frac{( x + 8 )}{x - 9}

6 = \frac{2 π}{b}

(x+33)/9 =(5x-3)/x

\frac{x + 33}{9} = \frac{5 x - 3}{x}

solvefor x,(-3)/x+y=15

so l v e f or x, \frac{- 3}{x} + y = 15