l(x)=(2x-5)/(5+x)

解

l (x) = \frac{2 x - 5}{5 + x}

x = \frac{- 5 l + 2 + 25 l ^{2} - 40 l + 4}{2 l}, x = \frac{- 5 l + 2 - 25 l ^{2} - 40 l + 4}{2 l}; l \neq = 0

解答ステップ

l (x) = \frac{2 x - 5}{5 + x}

以下で両辺を乗じる:

5 + x

l x (5 + x) = 2 x - 5

解く

l x (5 + x) = 2 x - 5 : x = \frac{- 5 l + 2 + 25 l ^{2} - 40 l + 4}{2 l}, x = \frac{- 5 l + 2 - 25 l ^{2} - 40 l + 4}{2 l}; l \neq = 0

x = \frac{- 5 l + 2 + 25 l ^{2} - 40 l + 4}{2 l}, x = \frac{- 5 l + 2 - 25 l ^{2} - 40 l + 4}{2 l}; l \neq = 0